The diameter wasn't asked, but if you want it this should give enough information to find it, somehow.Īnd yes, incidentally it also fits one circle more. It's easy to calculate that there is actually space left at the top, and since 7 is smaller than 8 there is space in the length-direction as well. And there is also room left at the top, so that the circles can be bigger since they can expand in height, and length. If you take a length 8, height 6 box, you can put 7 layers of 7 (diameter 1) circles in it. And in my case I think it does, and I'm sure that's also the case in James' solution. Just because I don't know the diameter doesn't mean larger circles don't fit. « Last Edit: Jul 2 nd, 2003, 4:37pm by Leo Broukhis » What is the smallest value of M*N such that an M cm by N cm rectangle can contain more than M*N identical circles, each with diameter 1 cm. ĭoc, I'm addicted to advice! What should I do?Īs neither towr, nor James specified the diameter, I tend to believe that they were solving a different problem: Wikipedia, Google, Mathworld, Integer sequence DB « Last Edit: Jul 3 rd, 2003, 3:33am by towr » I think 8*6=48, but I'm not quite sure, since my numbers change every 10 minutes (had lots of errors in my method). Some people are average, some are just mean.
« Last Edit: Jul 2 nd, 2003, 9:03am by Leo Broukhis » All circles must fit entirely within the rectangle at the same time, no circle may overlap any other circle.Ĩ4? And the diameter is 1.01036297108184508789. What is the smallest value of M*N such that an M cm by N cm rectangle can contain M*N identical circles, each with diameter greater than 1 cm? If M and N are integers, it is easy to fit M*N circles of 1 cm diameter into an M cm by N cm rectangle without the circles overlapping. Topic: Fitting Circles In A Rectangle (Read 17374 times) Hard (Moderators: Eigenray, Icarus, towr, ThudnBlunder, SMQ, Grimbal, william wu) RIDDLES SITE WRITE MATH! Home Help Search Members Login Register
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